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Light with a wavelength of 614.5 nm looks orange. What is the energy, in joules, per photon of this orange light? What is the energy in eV $\left(1 {eV}=1.602 \times 10^{-19} {J}\right) ?$

$\mathrm{E}=3.234 \cdot 10^{-19} \quad \mathrm{eV}=2$

Chemistry 101

Chapter 6

Electronic Structure and Periodic Properties of Elements

Electronic Structure

Periodic Table properties

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problem. Five. From Chapter six disaster has to provide energy per photons of orange light with the wavelength of 614.5 centimeters. So to solve this, we're going to have to use planks formula which is provided here. This states that the energy or E, is equal to planks constant h multiplied by the speed see divided by the wavelength Lambda as planks constant H and see the speed are constants. We already know those values and the question provides us with, um the nanometers of the wits of the wavelength, which is 614.5 centimeters. So we have all the variables that we need to solve this question. So once we've plugged those in, this is what we get. Um, so we have planks constant here, speed here, wavelength. Here it's important to note the units so the units for planks constant our jewel seconds, the units for speed, our meters per second and the units renowned for wavelength is Nana meters. Because speed is in meters per second, we're going to convert wth e wavelength from nana meters to meters so that the meter units can cancel out. So we're gonna go ahead and cancel these units. Nana. Meters, Nanometers, peters meters seconds. An inverse second. So what we're left with is Jules, which is a suitable unit for energy. But the question asks us to provide an answer in electron volts. Uh, the question provides the conversion from Jules to electron Volt, which is great eso. Once we multiply these two numbers together and divide by the nano meters, what we get is 3.233 times 10 to the minus 19 Jules. And then when we use the provided conversion from Jules to Electron Volt, um, we'll just cancel these Jule units out now, and they're in the same power, which is helpful. So once we divide this number by the conversion, we get the answer in electron volts, which is 2.18 electron volts.

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