00:01
Problem 5 from chapter 6 is asking us to provide the energy per photon of an orange light with the wavelength of 614 .5 nanometers.
00:10
So to sell this, we're going to have to use planck's formula, which is provided here.
00:16
This states that the energy, or e, is equal to planck's constant h multiplied by the speed c divided by the wavelength, lambda.
00:26
As planck's constant h and c, the speed, are constants, we already know those values.
00:35
And the question provides us with the nanometers, so the wavelength, which is 614 .5 nanometers.
00:46
So we have all the variables that we need to solve this question.
00:50
So once we plug those in, this is what we get.
00:55
So we have planx constant here, speed here, wavelength here.
01:02
It's important to note the units.
01:04
So the units for plank's constant are joules seconds.
01:07
The units for speed are meters per second...