00:03
In this problem, we have lithium reacting with nitrogen gas, and we are asked how many grams of lithium are required to completely react with 58 .5 milliliters of nitrogen gas at stp.
00:16
Stp is standard temperature and pressure.
00:19
It's equal to 273 kelvin as the temperature and one atm as the pressure.
00:25
So the first thing that we're going to do, we're looking for grams of lithium reacting with the volume of nitrogen so i'm going to go to moles first so we're going to take this volume of nitrogen gas and convert it to moles using the ideal gas equation so first we need to put this into liters we'll divide it by a thousand to do that so that'll be 0 .058 5 liters so now we'll use the ideal gas equation which is pv equals nrt p is the pressure which we have here v is the volume which we have here.
01:02
N is the number of moles.
01:03
That's what we're solving for.
01:04
R is a constant and t is temperature, which we have right here.
01:08
So if we just plug all of this in, one, atmospheres or pressure, our volume is 0 .058 .5 liters...