Question
Lithium reacts with nitrogen gas according to the reaction:$$6 \mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow 2 \mathrm{Li}_{3} \mathrm{~N}(s)$$What mass of lithium (in g) reacts completely with $58.5 \mathrm{~mL}$ of $\mathrm{N}_{2}$ gas at $\mathrm{STP} ?$
Step 1
4 L. Therefore, we can calculate the number of moles of nitrogen gas in 58.5 mL as follows: $$ n_{N_{2}} = \frac{58.5 \, mL}{22.4 \, L/mol} = 0.00261 \, mol $$ Show more…
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Lithium reacts with nitrogen gas according to the reaction: $$ 6 \mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow 2 \mathrm{Li}_{3} \mathrm{N}(s) $$ How many grams of lithium are required to completely react with $58.5 \mathrm{mL}$ of $\mathrm{N}_{2}$ gas measured at STP?
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Lithium reacts with Nitrogen gas according to the following reaction: 6 Li(s) + N2(g) → 2 Li3N(s) How many grams of lithium is required to completely react with 58.5 mL of N2 gas measured at STP.
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