Lithium reacts with nitrogen gas according to the reaction: 6 Li(s) + N2(g) → 2 Li3N(s) What mass of lithium (in g) is required to react completely with 39.1 mL of N2 N 2 gas at STP?
Added by Lindsey P.
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4 L. So, we can calculate the number of moles of nitrogen gas (N2) using the given volume. Number of moles of N2 = Volume of N2 / Volume of 1 mole of any gas at STP = 39.1 mL / 22400 mL = 0.001745 moles Show more…
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