Question
$$\log _{2}(3-x)+\log _{2}(1-x)=3$$
Step 1
For this, we need $3-x > 0$ and $1-x > 0$. This gives us $x < 3$ and $x < 1$. Combining these two inequalities, we get $x < 1$. Show more…
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log x (x-3)=log 2(x+3)
log 2(x-1)=3
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