Question
Magnesium has an HCP crystal structure, a $c / a$ ratio of $1.624,$ and a density of $1.74 \mathrm{g} / \mathrm{cm}^{3}$ Compute the atomic radius for $\mathrm{Mg}.$
Step 1
Here, $c = 1.624a$ and $a = 2r$ where $r$ is the atomic radius. Substituting these values into the formula, we get $V_c = 3\sqrt{3}(2r)^2(1.624*2r)/2 = 19.48r^3$. Show more…
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Magnesium (Mg) has an HCP crystal structure and a density of $1.74 \mathrm{~g} / \mathrm{cm}^{3}$. (a) What is the volume of its unit cell in cubic centimeters? (b) If the $c / a$ ratio is $1.624$, compute the values of $c$ and $a$.
Metallic magnesium has a hexagonal close-packed structure and a density of $1.74 \mathrm{~g} / \mathrm{cm}^{3}$. Assume magnesium atoms to be spheres of radius $r$. Because magnesium has a close-packed structure, $74.1 \%$ of the space is occupied by atoms. Calculate the volume of each atom; then find the atomic radius, $r$. The volume of a sphere is equal to $4 \pi r^{3} / 3$.
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