74 g of magnesium. We can do this by using the molar mass of magnesium (24.305 g/mol) and Avogadro's number ($6.02 \times 10^{23}$ atoms/mol). The number of atoms in 1.74 g of magnesium is given by:
\[1.74 \, \text{g Mg} \times \frac{1 \, \text{mol Mg}}{24.305 \,
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