00:01
In this problem, we're going to talk about circular motion.
00:04
So consider that we have an object performing a circular trajectory as this one here of radius r.
00:13
And we want to calculate the centripetal acceleration of this trajectory.
00:19
So the centripetal acceleration is equal to the speed of the object square divided by the radius of the trajectory.
00:29
Also, remember that as v can tell you, be written as the angular velocity times r, the acceleration is the angular velocity squared times times.
00:45
Also, so remember that omega is 2 pi over the period of rotation t.
00:56
Okay, one more thing we need to remember is that the gravitational force between two bodies is g times the mass of one of the objects times the mass of the other one divided by r square, where r is the distance between the two of them.
01:12
In our problem, we have mars that has a mass of 6 .42 times 10 to the 23 kilograms, and a period of rotation of 24 hours and 37 minutes.
01:33
Okay, and we want to put a satellite...