$\mathrm{H}_2 \mathrm{C}=\mathrm{CHCH}_2 \mathrm{Cl}$ is solvolyzed faster than $\left(\mathrm{CH}_3\right)_2 \mathrm{CHCl}$. Explain.
Solvolyses go by an $\mathrm{S}_{\mathrm{N}} 1$ mechanism. Relative rates of different reactants in $\mathrm{S}_{\mathrm{N}} 1$ reactions depend on the stabilities of intermediate carbocations. $\mathrm{H}_2 \mathrm{C}=\mathrm{CHCH}_2 \mathrm{Cl}$ is more reactive because
$$
\left[\mathrm{H}_2 \mathrm{C}=\mathrm{CH}=\mathrm{CH}_2\right]^{+}
$$
is more stable than $\left(\mathrm{CH}_3\right)_2 \mathrm{CH}^{+}$. See Problem 6.35 for a corresponding explanation of stability of an allyl radical.)