Question
$\mathrm{y}$ component of $\mathrm{A} \rightarrow \times \mathrm{B}^{-}$ is.$\mathrm{A}^{\rightarrow}=\mathrm{Ax} \hat{\imath}+\mathrm{Ay} \hat{\mathrm{j}}+\mathrm{A} z \mathrm{k}^{\wedge}$$\mathrm{B}^{\rightarrow}=\mathrm{Bx} \hat{1}+\mathrm{By} \hat{\jmath}+\mathrm{Bzk}^{\wedge}$(A) $A x B y-A y B x$(B) $\mathrm{Az} \mathrm{Bx}-\mathrm{AxBz}$(C) $\mathrm{AxBz}-\mathrm{AzBx}$(D) $\mathrm{AzBy}-\mathrm{AyBz}$
Step 1
The first row of the matrix is the unit vectors $\hat{\imath}$, $\hat{\jmath}$, and $\hat{k}$, the second row is the components of vector $\mathrm{A}$, and the third row is the components of vector $\mathrm{B}$. Show more…
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Key Concepts
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Vectors and Scalars
Section D
$$ z=a x+b y+a^{2}+b^{2} $$
Partial Differential Equations
Introduction
Transcript
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