00:01
Let's start by writing down some things that we know.
00:04
We know the ph is 9 .8.
00:08
So our h plus concentration, 10 to the negative 9 .8, it's going to be 1 .58 times 10 to the negative 10 molar.
00:19
Okay, and for our methylamine, right, we have a kb, and that is 4 .2 times 10 to negative 4 .4.
00:32
So for the conjugate acid of our methylamine, we'll write it's k -a, right, k -w over kb is k -a, so that's 2 .4 times 10 of the negative 11.
00:48
And that we know for a buffer solution, our h -plus is k -a times our moles of acid over our moles of base.
00:59
So i'm going to use the information that we know to find this ratio, because i want to once i have that ratio, i can use it to find moles of my acid.
01:09
So let's go ahead and rearrange that a tiny bit.
01:13
Our moles of acid over our moles of base is going to be h plus over ka.
01:28
So our h plus is 1 .58 times 10 to negative 10.
01:35
Our ka is 2 .4 times 10 to negative 11.
01:40
So this ratio is going to be 6 .6 to 1.
01:46
So let's find out how much of our conjugate acid we have...