00:01
All right, so he jumped a distance of 8 .95 meters.
00:26
We want to use g of 9 .80 meters per second squared.
00:35
How much less was powell's? okay, so if we launch a particle at 9 .5.
01:03
Meters per second squared, then v.
01:08
X is going to equal v.
01:10
Sub y, which is going to be the square root of 2 over 2, because that's the sign of 45 degrees, times 9 .5 meters per second squared.
01:22
Okay.
01:23
The velocity at the peak is going to equal velocity initial, which is the square root of 2 over 2, times 9 .5 is in the y direction, and that's 0.
01:51
V equals vp minus gt.
01:56
So t is going to equal square root of 2 over 2 times 9 .5 minus g, t, wait a minute, what am i doing? t is going to equal square to two over two times 9 .5 divided by g.
02:35
So that's going to be 0 .685 seconds, but that'll take halfway.
02:44
So that's to the halfway point...