00:01
A question here is x in us to a proof that 2x to the 3rd plus 5x square plus 6x plus 1 is equivalent to 0, mod 7.
00:17
That equation of that expression has three solutions.
00:24
Would you use the theorem 2 .29 from textbook? and if you want to look at the textbook, it was specifically the fifth edition of the introduction to the number, a theory of numbers by ivan navan at all, sockerman montgomery.
00:45
Okay, so let's look at that theory first.
00:52
That theory goes along the lines of, by the way, i have already worked in the problem.
01:01
And had it typed out.
01:03
So we're going to go through it.
01:06
Theorem, the theorem goes, let ffx be a polynomial of degree n with integer coefficients and p a prime.
01:18
Then the congruence, ffx equivalent into zero mod p has at most n incongruent solutions, modular p, right, has at most at most and in congruent solutions mod p.
01:37
So basically, look at this very important.
01:41
Look at the degree, look at the module of p.
01:43
So anyway, that's what the theorem says.
01:45
So let's look through how we solve this.
01:49
All right, so i got two steps here for you.
01:52
The first step is, again, i want to make it as very simple as possible.
01:58
First step would be to compute the modular 7, right, for the x values.
02:07
0, 1, 2, 3, all the weight is 6.
02:11
Okay? so that's the first thing we're going to do...