00:01
In this question, it is about adding electric fields from three coherent sources using phasers, phasal diagrams.
00:12
So we have e1 equals to e0, sine omega -t, and then we have e2 equals to e2 equals to e0, side omega t plus five then e3 is equal to e not i omega t plus two five okay so um in this question there are four parts we are supposed to find the resultant uh resultant view okay and in four different phase angles okay so so solution for part a, we want to do it for 5 equals to 20 degrees.
01:03
Okay.
01:04
So to do this kind of exercise, what we tend to do is we draw the phases.
01:12
Okay, with e1 at the horizontal, and then e2, and then e3.
01:19
Okay, so this is 20 degrees, and then this is 40 degrees.
01:25
Yeah.
01:25
So this is for part.
01:26
And then the resultant will be pointing in this way.
01:32
So this is ep.
01:37
So, ep in a vector form, okay, is e not.
01:45
So this is e1, u2, e3.
01:51
Okay, so then we just add then like vectors.
01:59
So e1 is is just i had and then e2 is cosine 20 degrees i had plus sign 20 degrees j head and then for each tree you'll be cosine 40 degrees i head plus sign 40 degrees j heads okay and so if you group them together you get e0 times 2 .71 i had plus 0 .95 j head so the modulus of e .p okay, it would be 2 .71 square plus 0 .985 square root.
02:42
Okay, and you get 2 .88, of course, there's an e0, e not.
02:48
Okay.
02:50
Then you can find a phase angle.
02:56
Okay, so this phase angle will be tangent 0 .985 divide by 2 .71.
03:05
In radiant mode you get 0 .349 radiance.
03:12
Okay.
03:14
So we can write our final answer to be ep is equal to 2 .8 0, sine omega t plus 0 .349 radiance.
03:26
Okay.
03:27
So this is how the resultant view will be written.
03:33
Okay.
03:35
Okay, then in part b, okay, we have 5 equals to 60 degrees.
03:43
Okay, so we repeat the same step...