Problem

Find the dimensions of a rectangle with area $ 10…

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Problem 7 Easy Difficulty

No question

Name: no question
Uploaded: 2019-11-15
Duration: 52 s
Channel: Numerade
Description: No question

Answer

Rectangle with maximum area is a square with side length 25 $\mathrm{m}$

Topics

Derivatives

Differentiation

Volume

Calculus: Early Transcendentals

Chapter 4

Applications of Differentiation

Section 7

Optimization Problems

Discussion

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Video Transcript

We know that if X is, our length and wise are within the perimeter is gonna be two times X plus y. We can set this equal to 100. Divide both sides by two. We get 50 equals X plus y Writing this in terms of why wise 50 minus axe area is X y, which gives us 50 acts minus X squared. Remember wise 50 minutes acts The derivative of area is 15 minus two acts said this equal to zero. We end up with 25 equals acts and then remember 50 minus 25 is why there for 25 is why so maximum areas a square with side length of 25 meters.

Amrita B.

Topics

Derivatives

Differentiation

Volume

Calculus: Early Transcendentals

Chapter 4

Applications of Differentiation

Section 7

Optimization Problems

Problem

Find the dimensions of a rectangle with area $ 10…

Problem 7 Easy Difficulty

No question

Answer

Rectangle with maximum area is a square with side length 25 $\mathrm{m}$

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 2 / BC Educators

Kristen K.

Samuel H.

Michael J.

Joseph L.

Calculus 2 / BC Bootcamp

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Watch More Solved Questions in Chapter 4

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 2 / BC Educators

Kristen K.

Samuel H.

Michael J.

Joseph L.

Calculus 2 / BC Bootcamp

Integration Review - Intro

Definite vs Indefinite

Recommended Videos