00:01
Hello everyone this is the problem based on nuclear fusion in the sun.
00:08
In the sun the energy is released due to fusion of hydrogen into helium and in the core helium into carbon.
00:23
So here we have to calculate.
00:25
I am not going to read complete paragraph this is quite lengthy.
00:30
So directly we are discussing the problem a.
00:35
Here it is asked if both the protons are moving with the same speed and they collide head on.
00:45
So this is one of the proton, this is another proton.
00:54
If they are colliding head on with same velocity, b1 is equal to b2, the radius of the proton is given 1 .2 into 10 to the power of minus 15 meters.
01:20
What is the minimum speed required for fusion to occur? so basic concept to solve this problem is conservation of energy.
01:32
When they collide, kinetic energy convert into potential energy.
01:36
So kinetic initial energy is kinetic and kinetic energy must be equal to potential energy of interaction when fusion will take place.
01:46
So it will be half mb square for one proton, half mb square for other proton and that will be k, q1, q2 ,y are potential energy.
01:57
Of interaction.
01:59
So from here we can find the velocity that will be k e squared charge on proton is plus e charge on another proton is plus e so k a square divided by m into r substitute the value you will get the answer.
02:23
K electrostatic force constant 9 into 10 to the power 9 is charge on proton m mass of proton and separation between them is 2 r 2 into 1 .2 into 10 to the power of minus 15 meter.
02:55
So on solving it, you will get the speed to be 7 .26 into 10 to the power 6 meter per second.
03:09
So this is the answer of part a.
03:15
Now we start solving the part b.
03:18
In the part b it is asked for helium helium collision.
03:23
What should be the speed? so concept to solve is same.
03:33
Helium b part for fusion of helium nucleus.
03:45
Charred on helium nucleus is plus 2e.
03:51
Mass is 4 times of that of proton that is 4 into 1 .67 into 27 k .g and the radius is given 3 .5 into 10.
04:16
10 to the power of minus 15 meters.
04:22
So concept will be the same.
04:24
If both are moving towards each other with same velocity, then kinetic energy should be equal to potential energy of interaction...