Of the four types of performance curves typically observed...

Name: Problem 2, Chapter 5: Motor Learning and Control: From Theory to Practice
Uploaded: 2020-07-27T23:17:39-08:00
Duration: 5 min 54 s
Channel: Ankit Gupta
Description: Of the four types of performance curves typically observed when learning motor skills, the one that is consider "normal" or "standard" is the a. linear performance curve. b. positively accelerating performance curve. c. S-shaped performance curve. d. negatively accelerating performance curve.

Of the four types of performance curves typically observed when learning motor skills, the one that is consider "normal" or "standard" is the a. linear performance curve. b. positively accelerating performance curve. c. S-shaped performance curve. d. negatively accelerating performance curve.

Of the four types of performance curves typically observed when learning motor skills, the one that is consider "normal" or "standard" is the
a. linear performance curve.
b. positively accelerating performance curve.
c. S-shaped performance curve.
d. negatively accelerating performance curve.

Key Concepts

Negatively Accelerating Performance Curve

The negatively accelerating performance curve is characterized by a steep improvement in performance during the early stages of practicing a skill, followed by a gradual slowing down of gains as practice continues. This pattern is considered 'normal' in motor skill learning as it reflects rapid initial progress that eventually tapers off as the learner approaches their maximum level of proficiency.

Motor Skill Learning

Motor skill learning refers to the process by which individuals acquire and refine movements through practice. It involves the gradual improvement of performance and efficiency over time as neural and muscular adaptations occur in response to repeated execution of a movement or task.

Performance Curve

A performance curve is a graphical representation that depicts the relationship between practice or time and the level of performance achieved during motor learning. It illustrates how performance changes, showing trends such as rapid initial improvement and later plateaus, which are common in skill acquisition.

Transcript

00:01 In this question, the performance p of t, a function of a learner, is given as m minus c e to the power minus k t.

00:16 Now if we want to find an expression here for p, we can rearrange this equation as c e to the power minus k t is equal to m minus p.

00:28 Therefore e to the power minus k t is equal to m minus p upon c now taking natural logarithm on both sides we will get ln of e to the power minus k t is equal to ln of m minus p upon c now on the left side this will become minus k t and ln of e is one and on the right side we will have ln of m minus p minus ln of c.

01:04 Therefore, t is equal to 1 upon k times if we multiply the negative sign inside, we have lnc minus ln of m minus p.

01:17 This is an expression for t in terms of p and the other constants.

01:26 Next in the question we are given an example of a performance function for a given learner where p of t represents the height he can jump and the function is given as 20 minus 14 e to the power minus 0 .024 t and it is said that if p of t is equal to 12 feet then we need to find how much t is.

02:06 Now to solve this we will put these values in the equation so we have 12 is equal to 20 minus 14 e to the power minus 0 .024 t.

02:19 On rearranging we will get 14 e to the power minus 0 .024 t is equal to 20 minus 12 which is 8.

02:30 Therefore e to the power minus 0 .0.

02:34 024 is equal to 8 upon 14.

02:38 Now if we take natural logarithm on both sides again, we will get on this side minus, okay, let us take ln of e to the power minus 0 .024t is equal to ln of 8 upon 14.

02:54 Now on the left side this will become minus 0 .024t and ln of e is 1.

03:02 And on the right side we have ln of 8 upon 14 now this value will be minus 0 .24 approximately so therefore p is equal to minus 0 .24 upon minus 0 .024 which is 10 months now this is an approximate value because as we calculated ln of 8 upon 14 is approximately or close to minus 0 .0 .0...

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