00:01
For part a, the isomer of c5h12 that produces four different monoclorination products is 2 -methylbutane.
00:36
So two methylbutane would be this structure here.
00:49
So two methylbutane.
00:52
And the four different monochlorination products would be one chloral, two methylbutane, two chloral, two methylbutane, three chloral, two methylbutane, and one chloral, 3 methyl butane.
01:48
So there would be the four different monoclorination products that would result from the 2 methylbutane.
01:54
That's the structural isomer of c5h12.
01:58
For part b, we are asked, when c4h8 is reacted with h2 or tertiary alcohols produces a major product, what is the structure of c4h8 in this reaction? so the c4h8 isomer that produces a tertiary alcohol is two methyl propane.
02:59
So two methyl propane would be the structure, ch2, c, c, c, h3, c, h3, c.
03:10
H3.
03:11
So there would be the isomer of c4h8 that would produce a tertiary alcohol.
03:18
For part c, when c7h12 is reacted with hydrochloric acid, one chloro, one methyl cyclohexane is produced as a major product.
03:26
What are the two possible structures of c7h12 in this reaction? the two possible structures of c7h12 are, now these would be isomers of one another.
04:02
Two, three, four, five, six.
04:05
We have double bond here.
04:08
Ch3, h, h.
04:19
So here is one isomer.
04:24
And then the second isomer would be this isomer here...