00:01
Today we have a reaction of ammonia and fluorine and a few questions and answer about that.
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Some stoichiometric questions and problems.
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Intervalating different substances in here, interpreting them in terms of moles or mass or virtually anything.
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Let's see what we have.
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The first part here, question is to figure out if we want to make four moles of hydrogen fluoride, how many moles of the ammonia and h3 we would need and how much of the fluorine we need.
00:36
So these are all that would be a classic mole -mole calculation.
00:41
So we're just looking at really these subscript or coefficients here.
00:47
Coections would be the number of moles of each substance.
00:52
All right.
00:52
So simple conversion.
00:55
I'm going to take my six moles of hf and put it in the, denominator, omitting the unit mole here to make things a little bit easier.
01:06
So the reason that works is because you want to convert it.
01:10
So you want to remove that preceding unit.
01:12
All right.
01:13
So we're trying to figure out here.
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I'm going to do the five fluorines, five moles of fluorine.
01:20
I'm going to do fluorine first here in this example.
01:23
So i have four moles of hf times the ratio of five to to six, five moles of fluorine to six moles of hf.
01:32
And the outcome of that is a 3 .33 moles of f2.
01:41
That's how much would be made.
01:43
So now i'm going to do the ammonia.
01:45
All right.
01:46
So i always put the denominator here to make sure that i have the units and labels canceling here.
01:54
So again, the six moles of hf in the bottom.
01:58
I look at it.
01:59
I have two moles of ammonia, so i just put two there.
02:03
So i got four times two divided by six...