00:01
We know that when x is equaling that minimum x distance, we can say that the rod is on verge of slipping.
00:12
And when the rod is on the verge of slipping, we know that then the frictional force is equaling the static frictional force max.
00:20
This would be equalling the coefficient of static friction times the normal force.
00:25
Or we can say the frictional force would simply be equaling 0 .50n.
00:31
Normal force.
00:32
So applying the newton second law, we have the sum of forces in the x direction equaling zero.
00:37
This will give us that the normal force minus the tension cosine of 37 degrees equals zero.
00:44
And so the normal force is simply equalling the tension force times cosine of 37 degrees.
00:49
Now we know that then the force would be equaling to 0 .50 neutens multiplied by tension times cosine of 37 degrees.
01:03
And this is approximately equaling to 0 .40 times t the tension force.
01:09
Now, we can say that the sum of the forces in the wire direction is equaling zero...