Question
One of the common tangents of $\mathrm{x}^{2}+\mathrm{y}^{2}=\frac{\mathrm{a}^{2}}{2}$ and $\mathrm{y}^{2}=4 \mathrm{ax}$ is(a) $y=x+a$(b) $y=-x+a$(c) $x=y+a$(d) $x+y=2 a$
Step 1
We need to find the common tangent of these two curves. Show more…
Show all steps
Your feedback will help us improve your experience
Saurabh Chandra and 56 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The equation of common tangents to the parabola y^2 = 8x and hyperbola 3x^2 - y^2 = 3 is: A. 2x ± y + 1 = 0 B. 2x ± y - 1 = 0 C. x ± 2y + 1 = 0 D. x ± 2y - 1 = 0
An equation of a tangent common to the parabolas $y^{2}=4 x$ and $x^{2}=4 y$ is (a) $x-y+1=0$ (b) $x+y-1=0$ (c) $x+y+1=0$ (d) $y=0$
For the two circles $x^{2}+y^{2}=16$ and $x^{2}+y^{2}-2 y=0$ there is/are (A) one pair of common tangents (B) two pairs of common tangents (C) three common tangents (D) no common tangent
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD