00:01
And now we do problem 180, 103.
00:04
And 103, you have combustion of one type of 2mm of carfid acid.
00:18
And this combustion yields 220 milligram carbon dioxide and 40 .3 milligrams of water determine the empirical formula of carfid acid.
00:30
This problem similar to the problem one or one.
00:36
So you have to find the mass of carbon, mass of hydrogen, and also mass oxygen too.
00:42
Right? and then you do similar way.
00:45
And now let's see we have one or three.
00:57
We have 2 -20 milligram carbon dioxide.
01:05
This is equal 0 .2 .2 .0.
01:09
Carbon dioxide.
01:11
You should see the problem 101, how i do conversion.
01:15
And then we have 40.
01:19
How many grams? 40 .3 milligrams.
01:28
40 .3 milligram of water.
01:33
And this equal 04040m of water.
01:41
And this equal 0403 in carbon and hydrogen in this amount right and now mass of carbon this this must be equal more of carbon a many gram here you get 0 .06 gram okay and then we do for the hydrogen we do similar way mass of hydrogen this equal this equal 0403 grams.
02:54
Tie 1 -0.
02:58
No, but water here too.
03:05
We should get a unit if no cannot cancel.
03:21
And then we type 2 more of hydrogen over 1 more of water.
03:30
And then we type a mass of hydrogen.
03:32
This equal 0 .0 .0 .05.
03:51
0 .05.
04:04
0 .0 .45 gram.
04:10
Okay.
04:12
And now we find mass of our oxygen...