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In this video, let's look at compounds that do not follow as when we're drawing the lewis structure, the octet rule.
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So just a reminder, the octet rule is basically stating that every atom in the compound, in the structure, needs to have eight valence electrons that it kind of has at its disposal.
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Okay.
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So that's the octet rule, but sometimes we can see some exceptions to that, and we're going to look at that right here.
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So let's look at this first one right here.
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So we have beryllium, high, or let's see, how would you say that? but beryllium and two hydrogen.
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And so anyways, when we look at this, we have beryllium, which is over on the left side of the periodic table.
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We always want, we'll just follow the same kind of process when drawing these valence electrons, but we have two valence electrons with beryllium.
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And then we have one valence electron each for each hydrogen, making a total of four balance electrons.
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On this molecule on this compound and so we're going to put brilium in the center we draw our hydrogens and you're going to notice something right here we've already used up all four of those valence electrons just by drawing the bonds to hydrogen and remember hydrogen's going to follow what we call the duet uh duet rule and the duet rule basically states that hide and this only applies to hydrogen but it needs two valence electrons only.
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Okay, but beryllium would follow the octet rule and it needs to have eight to be able to follow this, but you can see right here we don't have any electrons extra to donate to it, and right now it only has four valence electrons.
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And so this is an example.
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This is the correct lewis structure for this molecule, but you can see this exception right there that according to this, it does not have its full eight valence electrons.
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Let's look at another one right here...