00:01
Okay, so the first part of this question, they're asking for the empirical formula of carbohydrates.
00:06
So let's just say glucose, for example, c6, h2o6.
00:11
If we were to divide these subscripts by six, right, we would get ch2o as our empirical formula for glucose.
00:22
Now, since we divided all of these subscripts by six, what we can also do is we put a parentheses around it and we put a six down here.
00:29
This means that all of these elements are going to be multiplied by six, right? or we can write it more generally as ch2o, n.
00:43
M can be any number.
00:46
Now for part two, they want to know if we had 211 grams of ses, how many grams of carbohydrate is formed if the reaction has a 78 .5 % yield.
01:02
So the first step is to find the molecular weight of iron fes, right? so iron is 55 .845 grams per mole plus sulfur, which is 32 grams, right? so 55 .845 plus 32 grams gives us 87 .845 grams per mole.
01:37
So now what we do is we take the 2001 grams that we started with of fes.
01:48
We do a multiple...
01:50
We convert this grams into mows...