00:01
Now we do problem 131.
00:07
In this problem 131, you see we had the two reactants.
00:13
And the rectangle, they give you the amount 1 .5 grams of ion sulfide and 0 .252 more of carbonic acids.
00:25
So you must decide which one is the limiting reactant.
00:30
And the products, the mass of the products, must depend.
00:34
Then must be based on the mass of the limiting reactant here.
00:39
So we have to use both information to calculate the mass of ion 2 oxide.
00:47
So 1, 3, 1, 1, 1, 1, 1, yes, 1, 3, 1.
00:55
And we have to write equation again...