Question
Organice las siguientes disoluciones $0.10 \mathrm{M}$ en orden de acidez creciente ( $\mathrm{pH}$ decreciente): (i) $\mathrm{NH}_4 \mathrm{NO}_3$; (ii) $\mathrm{NaNO}_3$; (iii) $\mathrm{NH}_4 \mathrm{C}_2 \mathrm{H}_3 \mathrm{O}_2$; (iv) $\mathrm{NaF}$; (v) $\mathrm{NaC}_2 \mathrm{H}_3 \mathrm{O}_2$.
Step 1
En este caso, los ácidos son $\mathrm{NH}_4^+$ y $\mathrm{C}_2 \mathrm{H}_3 \mathrm{O}_2^-$, mientras que las bases son $\mathrm{NO}_3^-$ y $\mathrm{F}^-$. Show more…
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Arrange the following $0.10 \mathrm{M}$ solutions in order of increasing acidity (decreasing pH): (i) $\mathrm{NH}_{4} \mathrm{NO}_{3}$ (ii) $\mathrm{NaNO}_{3}$, (iii) $$ \mathrm{CH}_{3} \mathrm{COONH}_{4} \text { , (iv) } \mathrm{NaF} \text { , (v) } \mathrm{CH}_{3} \mathrm{COONa} \text { . } $$
Arrange the following 0.10 M solutions in order of increasing acidity: (i) NH4NO3, (ii) NaNO3, (iii) CH3COONH4, (iv) NaF, (v) CH3COONa.
Arrange the following 0.10$M$ solutions in order of increasing acidity: (i) $\mathrm{NH}_{4} \mathrm{NO}_{3},(\mathrm{ii}) \mathrm{NaNO}_{3},(\mathrm{iii}) \mathrm{CH}_{3} \mathrm{COONH}_{4},(\mathrm{iv})$ $\mathrm{NaF},(\mathrm{v}) \mathrm{CH}_{3} \mathrm{COONa}.$
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