Question
Perform each indicated operation. Simplify if possible.$\frac{x+8}{x^{2}-5 x-6}+\frac{x+1}{x^{2}-4 x-5}$
Step 1
The factorization of $x^{2}-5x-6$ is $(x-6)(x+1)$ and the factorization of $x^{2}-4x-5$ is $(x-5)(x+1)$. So, the expression becomes: \[\frac{x+8}{(x-6)(x+1)}+\frac{x+1}{(x-5)(x+1)}\] Show more…
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