00:01
Okay, so for part of this question, they want us to balance the following reaction.
00:04
So let's start with pb.
00:07
We have two pb on the right side.
00:10
And we have one on the left side.
00:12
So in order to balance it out, we need to add a two in front of the pbo.
00:16
This gives us two lead on both sides.
00:20
Now next, let's do cl.
00:23
We have two cls on the right side.
00:28
But we only have one on the left side.
00:30
So in order to balance it out, we just need to add a two in front of the end.
00:32
Nacl and we have two cls on both sides.
00:36
Then let's do sodium.
00:39
We have one times by the two.
00:41
We have two sodiums on the left side.
00:45
But we only have one sodium on the right side.
00:47
So in order to bounce it out, all we need to do is add a two in front of naoh.
00:52
And we had two sodiums on both sides.
00:56
Now let's do carbon.
00:57
We have one carbon on the left.
00:59
We have one carbon on the right.
01:02
So carbon is balanced.
01:03
Now let's do oxygen...