00:01
For this exercise, we have a light of 350 nanometers of wavelength shining on a certain metal plate.
00:14
And we're also given the information that the smallest potential that can prevent any electron from reaching the other electrode is 1 .1 volts.
00:26
Okay.
00:26
And then we're asked to calculate the maximum wavelength that i'm going to call lambda n that the photons can have in order to remove an electron from that metal blade.
00:44
So that's what we're going to calculate.
00:47
So the first thing we had to do here in order to solve this exercise is to calculate the work function.
00:54
So let's calculate the work function.
01:04
Notice that we have here the smallest potential that will prevent any electron from reaching the other electrode.
01:12
This means that the kinetic energy of the electrons will be e, the charge of the electrons, times v, the potential.
01:22
And this is going to be, according to the photoelectron equation, this is going to be hf minus the work function.
01:32
But f can be rewritten as c over lambda and from here you can isolate phi the work function that's what we're interested in calculating here so h times c is 1240 electron volts nanometers divided by 350 nanometers and e times v and e times v notice that v is 1 .1 volt, so e times v is 1 .1 electron volt, and this calculation here results in 2 .4 electron volts...