00:01
Okay, and this problem we're told, we have point charges of 15 minus 25 microculems, and they're placed one meter apart.
00:08
So i'll go ahead and draw that q1, q2.
00:17
Fix this a bit.
00:22
Q1 and then q2.
00:25
Some distance are apart.
00:29
You know, r is equal to one meter.
00:35
And then q1 is minus 50.
00:40
Times 10 to the minus 6 coulomes, and q2 is minus 25 times 10 to the minus 6 couloms.
00:56
And we want the force on a third charge, q3, if it's placed midway between these.
01:03
So kind of acknowledging that they're both negative charges, and then acknowledging that q3 is positive, q3 is going to feel an attraction.
01:14
To both so the forces are going to subtract um so the force from q2 i'll call put a little two under here to label that is to the right and so by convention i'll say to the right is positive and then the force from q1 is negative um so adding up the net force we get force is equal to um so we're going to do the force from two so that's k q2 q2 q 3 over r squared and then i'm just going to use magnitudes i'm going to use all positive numbers here i don't have room for the magnitude symbols i'll just put them in okay and then the distance between q3 and q2 is r over 2 so that's going to go in this denominator squared right because the kulom's force is k qqq over r squared and then where r is the actual distance between q3 and q2 which is half of what i'm calling r, which is one meter...