00:01
Okay, so we have this problem.
00:03
The velocity is measured.
00:06
V of t equal sine t on the interval 0 to 2 pi, and we know that distance at time t is equal to 1.
00:13
So we're going to start by graphing the velocity.
00:18
So the velocity is sine of t.
00:20
So the sign of, if we started 0, sine of 0 is equal to 0.
00:25
We can do this in red.
00:26
So we got 0.
00:27
Sine of pi over 2 is equal to 1, sine of pi is equal to 0, sine of 3 pi over 2 is equal to negative 1, and sine of 2 pi is equal to 0.
00:43
So we get ourselves on that curve like that, and we can find out that the intervals on here.
00:49
So the positive interval, so the positive interval for v of t is when t is going from 0 to pi, the negative interval is, is from pi to 2 pi.
01:11
Then we have, we're going to figure out the anti -derivative because we're trying to figure out the distance.
01:20
Because remember, the velocity is the derivative of the distance...