00:01
Okay, problem 28 .6, we have two point charges of positive charge, of certain values, and they're moving in different directions, and there's certain distance apart from this point p.
00:14
So first question is when two charges are locations shown a figure, where the magnitude direction of the magnetic field they produce at point p.
00:22
Okay, so we're going to start off with writing the magnetic field of a moving point charge.
00:27
So we have b and then at.
00:32
Point p we're going to write is equal to mu not over four pi and then i'm going to write down one over distance squared and that's going to be similar between the two different terms so we have a term that's for the positive charge q and one for positive charge q prime and then in brackets i'm going to put down what the difference between those terms are because it's the same we're going to write on what's different and then they're just going to be added together so one is is going to be the charge times the vector v cross r hat.
01:10
So for the first one, we have qv, and then it's going to be the unit vector i hat cross with negative to j hat.
01:22
So i hat, cross with negative j hat.
01:26
That's the unit vector for the velocity crossed with the r hat vector extending from point to point q to be.
01:36
And then that's going to be added to q prime, v prime, charge, velocity, and it's going to be negative i -hat, it's going left, cross with positive j hat.
01:49
So negative i hat, cross with j hat.
01:57
Okay, so then that's going to then be equal to the same constants, v0 over for pi over d squared, and it's going to be the numbers we have here so it's going to be 8.
02:14
Now i'm just going to read this.
02:17
So q, v, i hat cross negative j hat is going to be negative k hat.
02:27
And then plus q prime, v prime.
02:32
And then we have negative i hat cross j hat.
02:35
That's going to be again negative k hat.
02:41
Okay, so then all this is numbers.
02:44
And then we have the negative k hat for each of them.
02:46
So if you solve that, we get four, three, three, 7 .5 micro tesla and a negative k -hat direction.
03:00
Okay, so that's part a.
03:04
Part b was magnitude direction of electric and negative fields.
03:10
Excerts on each other.
03:13
Okay, so first off, i'm going to start with the next page.
03:21
So we have the force, the electric field of key.
03:27
Acting on q prime that's going to be one over four pi epsilon not and then q prime q over 2d square two d is a distance that separates them q prime to q this is just coombs law okay so then that's just all calculate out that's all numbers we have so 3 .74 new and then we have to figure out what the direction is and that's going to be negative j hat.
04:09
So if we go back to the first page, q acting on q prime, those are both positive charges.
04:15
It's going to repel q prime is going to be pushed down, which is negative j hat.
04:20
Okay, and then due to symmetry in the calculation, the force of the electric field, q prime, acting on q, it's just going to switch those to q and q prime, but that's going to be the same value.
04:43
So then we just get 3 .74 newtons and a positive jad direction.
04:52
So the, oops, so the top charge is going to be repelled, push up.
04:59
Okay, so how about the next one? so force of due to the b field of q acting on q prime...