00:01
Hi, my name is arusa and i am here to answer your question.
00:04
So we will start with reaction number one.
00:11
Reaction number one.
00:20
And we will write into different steps.
00:24
So step number one is a reaction between two cyclo, sorry, two methyl propane, which is ch2, double one.
00:38
C c h3 c hc3 plus hl okay so in this reaction what actually happens is that okay i can write um this hl in a different way so it's easier for you to understand i will write it like this okay what will happen here is that this double one will actually um attack on the hydrogen and this one will come uh with chlorine as a negative chart and as a result, we will get something like ch3, c, ch3 positive plus c l negative.
01:27
Because this double bond is broken.
01:29
And now this central carbon, it should have four groups around it, and now it has only three groups attached to it.
01:37
So it will get a positive charge.
01:39
And it's called a tertiary carbocitan.
01:42
In step number two, what will actually have? is that this cl negative will actually act as a nucleophile and it will attack on the tertiary carbon.
01:53
Okay, so i will write it here.
01:56
We have a tertiary carbocetine like this.
02:00
Ch3, ch3 plus cl negative, which will act as a nucleophile.
02:09
It will attack on this tertiary carbon.
02:12
And we will get the final product which is c, ch3, c, c, and we will get the final product.
02:20
Ch3, ch3, and cl.
02:24
And we can call it two methyl, two chloropropine, because the chlorine and a methyl group are attached on the second carbon.
02:35
Okay, we are done with reaction number one.
02:37
We can proceed to reaction number two, which is our second reaction, reaction number two.
02:48
And our second reaction is a reaction of a cyclohexene with hbr.
02:58
And it's the same reaction.
03:00
I will again write it in different steps.
03:03
So our step number one is where this double bond will actually attack on hydrogen...