00:01
Hi, my name is arosa and i'm here to answer your question.
00:04
So we will start with our first reaction, which is reaction number one.
00:12
Reaction number one.
00:15
And i will write it in different steps.
00:16
So it's easier for you to understand.
00:18
So in this step number one, which is basically c .h3, c .h2, c .h2, br, which is one bromopropane, and it is reacting with n -a -o -h.
00:44
So what will happen is that because this o -h, it will act as a nucleophile because it has an electron pair as well on the oxygen.
00:55
So this will attack this carbon atom.
01:00
Displacing this romaine.
01:02
That means when this will attack this carbon atom, this bond will be broken.
01:07
So as a result, in the products, we will see that i will write the product somewhere down.
01:15
Ch3, ch2, ch2, ch2, oh.
01:23
This oh will be attached to this carbon atom, and the product will be one bromopropane, 1 bromopropane plus this bra which has been detached from here it will form a bond with n .a...