00:01
In this exercise, we need to remember that the potential energy u of x is an energy associated with a force, such that the force of x is equal to minus the derivative of the potential energy u.
00:22
And we can write the conservation of energy as the initial kinetic energy, k -0 plus the initial potential energy u -0 is equal to the final kinetic energy kf plus the final potential energy uf.
00:40
And in our problem, we have, we model actually the potential between two nucleants to be equal to zero times one minus z to the minus x over x zero.
00:58
This is the potential generated by the strong force between the two nucleons where u0 is equal to 6 times cents of the minus 11 joules x0 is equal to 2 times center to minus 15 meters this is a typical nuclear distance and we also have the information that the mass of a nucleon is 1.
01:36
0 .67 times 10 to the minus 27 kilograms.
01:44
And also we have to model them as having a diameter of 1 times 10 to the minus 15 meters.
01:56
And in question a, our goal is to draw the potential energy, this potential energy here, either by hand or by using a software.
02:09
I chose to use a computer program.
02:12
You could do it by hand.
02:15
The situation would be the same.
02:18
I just plotted it using python, but you could do it using mathematica, matlab, or whatever program you are most familiar with.
02:32
So this here is our plot.
02:35
Notice that the potential energy always increases with x.
02:42
But it tends to a plateau.
02:45
So it will never be greater than 6 times 10 to the minus 11 joules.
02:52
Then in question b, we have to suppose that you hold the two nucleants at a distance of 5 times 10 to minus 11 meters apart, counting from their centers.
03:18
And we have to calculate the potential energy u and draw it in the graph.
03:25
So the potential energy u is u 0, 6 times 10 to minus 11 times 1 minus the exponential of 5 times 10 to the minus 11 divided by 2 times 10 to the minus 15 and actually i'm sorry this shouldn't be 5 2 times 10 to the minus 11.
03:50
Should be 5 times 0 to the minus 15 meters...