We notice that the numerator, $1-\sin^{2}x$, is a difference of squares. We can factor it as $(1-\sin x)(1+\sin x)$. The denominator is $1-\sin x$. Therefore, the left-hand side simplifies to:
$$\frac{1-\sin^{2}x}{1-\sin x} = \frac{(1-\sin x)(1+\sin x)}{1-\sin x}
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