Question
Prove that multiplication $M_h[f(x)]=h(x) f(x)$ by a given function $h \in \mathrm{C}^n[a, b]$ defines a linear operator $M_h: \mathrm{C}^n[a, b] \rightarrow \mathrm{C}^n[a, b]$. Which result from calculus do you need to complete the proof?
Step 1
Define the operator \( M_h \) by \( M_h[f(x)] = h(x) f(x) \) for a function \( h \) which is continuous and \( n \)-times differentiable on the interval \([a, b]\). The space \( \mathrm{C}^n[a, b] \) consists of all functions that are \( n \)-times continuously Show more…
Show all steps
Your feedback will help us improve your experience
Mohamed Mohamed and 78 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Let $f : A \rightarrow B, g : B \rightarrow C,$ and $h : C \rightarrow D .$ Prove that $h \circ(g \circ f)=$ $(h \circ g) \circ f(\text { associative property })$ [Hint: Verify that $(h \circ(g \circ f))(x)=((h \circ g) \circ f)(x)$ for every $x$ in $A . ]$
Functions and Matrices
Composition of Functions
Let $f(x)=a x^{2}+b x+c$. Show that $\frac{f(x+h)-f(x)}{h}=2 a x+a h+b.$
Functions
Shapes of Graphs. Average Rate of Change
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD