00:01
Now for the fly, in this case, to actually exhibit quantum behavior as it passes through a hole, right? the wavelength of the insect must be approximately in the same order as the diameter of the hole, which is given to be about 4 millimeters.
00:29
Now given this is our wavelength or the broglese wavelength of the fly, we can find what is its velocity based on lambda being equals to age over the momentum.
00:44
So momentum is age over wavelength.
00:51
And with this we can actually find the speed by dividing by the mass.
01:07
The mass of the fly is given to be 1 .25 mcg grams, so that's 10 to power minus 6 kilograms.
01:15
And the wavelength is 4 millimeters.
01:27
With this we should get about 1 .33 times 10 power minus 25 meters per second.
01:38
Now to find the total time required to pass through the thickness of the hole, that is given as 0 .5 millimeters, 0 .5 times 10 to power 5 to power.
01:56
Minus 4 meters...