00:01
So in this question we're asked to estimate the force exerted on the earth due to radiation pressure from the sun, given that the sun emits an intensity of 1 .4 kilowatts per meter squared, and it's absorbed by the earth, and we can treat the earth as a flat disk with the radius of the earth.
00:21
And then partly we're asked to compare the magnitude of this force to the force of gravitational attraction, and see which is bigger and which is.
00:32
And by how much.
00:34
So this question, we can begin then with part a.
00:39
So in part a, we're asked to determine the force due to radiation pressure.
00:44
So we're told that the light is absorbed.
00:47
So the radiation pressure formula that we can use is pr is equal to just the intensity of the sun, i, s, over the speed of light, since it's absorbed and not reflected.
01:00
So if we work to say this equal to 1 .4 by 10 to the speed 3 watts per meter squared over the speed of light which is 3 by 10 to the 8 meters per second and if we work this out this is equal to 4 .667 by 10 to the minus 6 pascal's but we know the relationship between force and pressure for pressure is equal the force per unit area so we have that the force then is equal to the pressure p r times the area of the surface area of the disk that we're taking to be the earth.
01:40
So this is equal to then, so the radiation pressure is 4 .667 by 10 to the minus 6.
01:49
And the area of the earth is taken to be disk.
01:52
And it's going to be pi or squared.
01:55
And the radius the earth is 6 .37 by 10 to the 6 all squared.
02:02
So if we work to say out, we get that the force is equal to 5 .949 times 10 to the 20 or 10 to the 8 newtons.
02:17
So that's our answer for a.
02:18
This is the force due to radiation pressure...