00:01
Okay, this problem is asking us to rank the compounds according to their oxidation levels.
00:05
So, for my purposes, i'm going to say that 1 equals most oxidized.
00:12
This means that 4 would be least oxidized, or at least most reduced.
00:17
Okay, so how do we think about oxidation levels in the context of different molecules? a good way to start would be to analyze the hydrogens.
00:28
So, for example, this compound, this cyclohexane, has two hydrogens associated with every carbon.
00:36
So i'm going to write down hydrogens for each of them.
00:38
Pretend that these each have hydrogens.
00:40
So that means that it has two, four, six, eight, ten, twelve hydrogens.
00:45
Twelve hydrogens, because we have six carbons, each of them have two.
00:49
Okay, for this one, we have only one hydrogen associated with each carbon.
00:54
That's because they each have double bonds.
00:58
This one we only have six hydrogens.
01:00
So comparing this one to this one, this one would be more reduced, meaning that this one is more oxidized.
01:07
This one is more reduced because it has more hydrogens.
01:10
Reduced is basically a term for having more hydrogens.
01:14
Okay, so we know that this one is more oxidized.
01:19
So for now i'm going to label this one and this one too, because one is most oxidized.
01:24
Okay, now let's look at this next one.
01:28
So, associated with this carbon, we have a carbon -oxygen bond.
01:32
And that is not considered a hydrogen.
01:34
So for right now, i'm going to skip over that.
01:37
Instead, i'm going to analyze the hydrogens.
01:39
So, hydrogens, hydrogens, hydrogens, hydrogens, hydrogens, hydrogens, and hydrogens.
01:45
So let's look at how many hydrogens...