Tertiary alkyl halides, $\mathrm{R}_{3} \mathrm{CX}$, undergo spontaneous dissociation to yield a carbocation, $\mathrm{R}_{3} \mathrm{C}^{+},$ plus halide ion. Which do you think reacts faster, $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}$ or $\mathrm{H}_{2} \mathrm{C}=\mathrm{CHC}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{Br} ?$ Explain. (FIGURE CANNOT COPY)