00:01
Okay, this problem is asking us to analyze these reactions and say what is wrong with them.
00:05
So if we zoom into the first one, we can see that we have an alkyl fluoride reacting with magnesium and acid workup to generate a propane molecule.
00:12
So is this correct? the answer is no, because alkyl fluorides have a very specific or very different reactivity with magnesium than do alkyl chlorides, alkyl chlorides, alkyl bromides, and alkyl iodides.
00:22
So if we were to create a greenerd, then we would have an acid workup, which would generate propane.
00:28
So, ideally, we want a greenered reagent and then acidify it using acid workup to generate propane.
00:34
But fluorine and magnesium do not combine to make a greenered reagent.
00:37
Instead, we would want something like chlorine or bromine or iodine.
00:42
So i'm going to just write bromine.
00:44
Okay, that would generate a greenerid reagent, and then we can make propane.
00:48
Okay, next step, we have an alkene reaction with nbs, and then we have our product.
00:54
Okay, so is this the correct reaction? the answer is no.
00:58
Product is not correct.
01:01
So let's look at our started material.
01:04
Our starting material has an alkene, and then one carbon away is our allelic carbon.
01:10
So surface level, if we were to have a radical here and we had a bromine here, this would be our reaction, which seems correct because we have the generation of the correct product off of that.
01:20
But this radical is not considered to be the most reactive.
01:24
We would want a better situation in which we have a bromine, the position of the roaming in a different spot because of the position of the radical being more reactive.
01:33
So, for example, let's say i have my alken.
01:37
I have two options as far as the allilic carbon in which the radical is associated with.
01:41
I can either have a radical here or i can have a radical here.
01:45
So which one is considered the most stable? the answer relies on the carbons in which they're attached to.
01:52
So i have a radical here.
01:54
That's one option.
01:55
That radical is on a one, two, secondary carbon...