00:01
Okay, this problem is asking us to find out whether we are dealing with a reduction, oxidation, or neither of them.
00:06
So a good place to start would be to draw the compounds.
00:10
If you've seen my other videos before, you might have noticed that i really like to draw the skeletal structures, and that is because within organic chemistry, i think that the easiest way to understand mechanisms and reactions in general is to draw the skeletal structures.
00:23
Okay, so that is why i'm drawing these skeletal structures.
00:25
The reagent that facilitates this reaction is cr -03.
00:31
If you've taken organic chemistry before or you recognize cro3, you might recognize it as an oxidizing agent, which means that this is an oxidation reaction.
00:42
If you have no idea what i'm talking about or you've never seen cro3, you might be questioning, how do i know that this is an oxidation reaction? and the answer to that is you look at the hydrogens.
00:52
So attached to the starting material, we see that we have two hydrogens, one, two, at carbon number two.
00:59
So two hydrogens on carbon number two, in the product attached to carbon number two, we only have the single hydrogen.
01:06
So we go from two to one hydrogen.
01:09
That means that we broke a ch bond.
01:14
If we broke a ch bond, that corresponds to an oxidation.
01:21
Okay, next step.
01:24
In this reaction, we are dealing with an alpha beta unsaturated ketone.
01:28
If you've never heard of that term, don't worry, it's not relevant, but basically we have an alken and we have a carbonyl.
01:35
But we're going to react that compound with nh3, and we're going to get this product.
01:49
Okay, so let's identify whether this is an oxidation, reduction, or neither of them.
01:54
A good place to start would be to first look at this alken.
01:57
We see that we have an alken and we ended up with an alken for that particular bond.
02:02
So if we have an alken, if we have a double bond, and we end up with a single bond, you might hypothesize that a reduction occurred, because in order to get rid of a double bond, you might have to add hydrogens across that double bond.
02:14
So let's hypothesize that this is a reduction reaction and see if we're right.
02:20
So we see that we have a hydrogen here and two other hydrogens on the double bond.
02:27
So three hydrogens total, 3h.
02:31
And the product, we have one, two hydrogens, and we also have one, two hydrogens.
02:39
So that means that we have four hydrogens total.
02:45
So looking at a surface level, we went from 3 hydrogens into 4 hydrogens.
02:50
That means that we formed a c -h bond.
02:57
But we have to look at the entire molecule because in the starting material, we only have this alken.
03:04
In the product, we have the formation of a c, that carbon right there, with a nitrogen...