Question
Rank the following compounds in order of increasing $\mathrm{S}_{\mathrm{N}} 2$ reaction rate with KI in acetone.methyl bromide $\quad$ sec-butyl bromide$A$B3-(bromomethyl)-3-methylpentane$C$1-bromopentane $\quad$ 1-bromo-2-methylbutane$D$
Step 1
The less steric hindrance, the faster the reaction rate. This is because the nucleophile needs to approach the carbon atom that is attached to the leaving group, and if there are many bulky groups around this carbon atom, the approach of the nucleophile will be Show more…
Show all steps
Your feedback will help us improve your experience
Aadit Sharma and 76 other Organic Chemistry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Rank the following compounds in order of increasing $\mathrm{S}_{\mathrm{N}} 2$ reaction rate with KI in acetone.
Rank the following compounds in decreasing order of their reactivity toward the $mathrm{S}_{mathrm{N}} 2$ reaction with sodium ethoxide $left(mathrm{Na}^{+-} mathrm{OCH}_{2} mathrm{CH}_{3} ight)$ in ethanol. methyl chloride tert-butyl iodide neopentyl bromide isopropyl bromide $quad$ methyl iodide $quad$ ethyl chloride
Rank the following compounds in decreasing order of their reactivity toward SN2 reaction with sodium ethoxide (Na+-OCH2CH3) in ethanol and please explain the reason. (a) methyl chloride (b) tert-butyl iodide (c) neopentyl bromide (d) isopropyl bromide (e) methyl iodide (f) ethyl chloride
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD