00:01
And this problem is asked to calculate the, or find the activation energy first by graphing, then by calculating.
00:08
And we're told with calculation tubes.
00:11
Okay.
00:13
So let's go ahead and add a couple things.
00:16
Let's add the ln of k and one over, this is my temperature in c.
00:30
So we're going to get my temperature in k.
00:33
One over k.
00:35
Okay, so our k temperature i'm going to put down here will be 478, 483, 488, 493, 498, 493, 498, and 503.
01:08
So 1 over k, this will be 2 .07 times, or 2 .09 times 10 to the minus 3, 2 .05, 2 .05, 2 .03, 2 .05, 2 .03.
01:29
2 .01, 1 .99 times 10 to the minus 3, times 10 to the minus 3.
01:40
And over here, i'm going to have the ln of k.
01:44
That will be negative 3 .9, negative 3 .6, negative 3 .9.
01:52
I got that.
02:05
Negative 2 .6, negative 2 .2 .2.
02:10
Okay, so let's go ahead and graph these with the ln.
02:18
Let me start here.
02:19
Let's start here at 0 .1, 2, 3, 4.
02:38
I wonder if i can go by 3, 2, 3.
02:55
And then i'm going to go by, this will be something times 10 to the minus 3.
03:06
So i'm going to have 1 .9, 1 .992, 2 .02.
03:32
4, 6, 8, 9, 9, 2, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
04:04
Okay, let's get my numbers in here.
04:07
This isn't going to be perfect.
04:08
If you stick this into a calculator, you will get better numbers than i do...