00:01
In this problem, the rate constant were measured at various temperatures for the given reaction.
00:08
And the following data was given.
00:10
We're going to use this data to determine the activation energy both graphically and using calculation.
00:20
So we're going to use the erroneous equation.
00:23
So when we graph the values of lnk versus 1 over temperature in kelvin, we're going to get a straight line graph.
00:32
Is going to be equal to negative activation energy over r, with r equal to 8 .314 joule per mole times kelvin.
00:42
So convert the temperatures to calvin by adding 273, and then take the reciprocals.
00:48
Then find the ln of the k values.
00:51
Then we're going to set the slope of this straight line equal to negative e8 over r.
00:57
So you can do this.
00:59
You can find the equation of the straight line using excel or another graphing program...