Question
Ratio of magnetic field at the centre of a current carrying coil of radius $R$ and at a distance of $3 R$ on its axis is(A) $10 \sqrt{10}$(B) $20 \sqrt{10}$(C) $2 \sqrt{10}$(D) $\sqrt{10}$
Step 1
Step 1: The magnetic field at the center of a current carrying coil of radius $R$ is given by $B_c = \frac{\mu_0 I}{2R}$. Show more…
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