Question
refer to the equation $A x^2+C y^2+D x+E y+F=0$, where $A$ and $C$ are not both 0 .Show that if $A \neq 0, C=0$, and $E \neq 0$, then the equation is equivalent to one of the form$$(x-h)^2=4 p(y-k)$$
Step 1
Since we are given that \( A \neq 0 \), \( C = 0 \), and \( E \neq 0 \), we can simplify the equation to: \[ A x^2 + D x + E y + F = 0 \] Show more…
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