By a translation of axes, (distinct) points $\mathbf{S}\left(x_1, y_1\right), \mathbf{T}\left(x_2, y_2\right)$, and $\mathbf{U}\left(x_3, y_3\right)$ are given new coordinates $\mathbf{S}^{\prime}\left(x_1^{\prime}, y_1^{\prime}\right), \mathbf{T}^{\prime}\left(x_2^{\prime}, y_2^{\prime}\right)$, and $\mathbf{U}^{\prime}\left(x_3^{\prime}, y_3^{\prime}\right)$, respectively. If $\mathbf{s}, \mathbf{t}, \mathbf{u}, \mathbf{s}^{\prime}, \mathbf{t}^{\prime}$, and $\mathbf{u}^{\prime}$ are the vectors corresponding to $\mathbf{S}, \mathbf{T}, \mathbf{U}, \mathbf{S}^{\prime}, \mathbf{T}^{\prime}$, and $\mathbf{U}^{\prime}$, respectively, verify algebraically that
$$
\frac{\left(\mathbf{t}^{\prime}-\mathbf{s}^{\prime}\right) \cdot\left(\mathbf{u}^{\prime}-\mathbf{s}^{\prime}\right)}{\left\|\mathbf{t}^{\prime}-\mathbf{s}^{\prime}\right\|\left\|\mathbf{u}^{\prime}-\mathbf{s}^{\prime}\right\|}=\frac{(\mathbf{t}-\mathbf{s}) \cdot(\mathbf{u}-\mathbf{s})}{\|\mathbf{t}-\mathbf{s}\|\|\mathbf{u}-\mathbf{s}\|}
$$
and interpret this fact geometrically.