refer to the equation $A x^2+C y^2+D x+E y+F=0$, where $A$ and $C$ are not both 0 .
Show that if $A \neq C$, but $A C>0$, then the equation is equivalent to an equation of one of the forms
$$
\begin{aligned}
& \quad \frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \quad \text { or } \quad \frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}=1 \\
& a>b>0, \text { provided } A\left(4 A C F-C D^2-A E^2\right)<0
\end{aligned}
$$